Cat Matroskin is the most charming and beloved by the audience character of the cartoon trilogy about Prostokvashino, filmed in 1978 - 1984:

However, the charm of the cat Matroskin was achieved by means purely external to Uspensky's text and is the merit of the artist N. Yerykalov and the actor O. Tabakov, who voiced this role. To verify this, it suffices to compare famous image with more early version- in the cartoon "Uncle Fyodor, a dog and a cat" (1975-1976).

Cat Matroskin does not have the first cartoon version and little bit the charm of that cat Matroskin, whom we all know. This is a creature with an unpleasant and somewhat malicious expression on his face, quite faithfully expressing his character.

If we ignore the charm of the cartoon image, then what is Matroskin the cat? This is a type of petty-bourgeois psychology that has been criticized many times in Soviet art.

He is obsessed with the idea of ​​starting a farm, buying a cow. For this, he is ready to sell his friend - Sharik:
"Come on, Sharik, we will sell you" (7:06).

For Matroskin, money is a priority, not labor. Having found a treasure with friends, he dreams: "Now we will buy a cow. And we don’t have to work in the garden. We can all buy in the market" (7:36).

His material interests clearly prevail over spiritual ones. Uncle Fyodor and Sharik decide to subscribe to magazines ("Murzilka" and a magazine about hunting, respectively), but Matroskin declares that he will not subscribe to anything, but will "save" (6:17).

Matroskin's attitude towards others is undisguisedly selfish. About the jackdaw: "Oh, we feed him in vain. Let him bring benefits" (9:41).

He declares to Sharik: "There is no income from you. There are only one expenses" (25:06). And he offers Uncle Fyodor to make a sled dog out of Sharik in order to carry milk to the market and spud the garden on it.

With his obsession with money, Matroskin practically drives Sharik to suicide. Sharik prefers to drown rather than return home without a gun, "for which money has been paid", but the beaver saves the dog ("Holidays in Prostokvashino").

Matroskin constantly talks about money. For example, when Uncle Fyodor's parents send Sharik a photo gun as a gift, Matroskin remarks that it "probably big money stands." Uncle Fyodor advises Sharik to take pictures of animals and send photos to magazines - Matroskin adds: "That's right. Where they pay more" (32:47).

But this phrase of Matroskin, which has become popular, is a direct mockery of the bourgeois on the idea of ​​​​communist labor - joint work for the common good:
"Because working together is for my benefit, it unites" (47:40).

Matroskin's mercantilism does not receive condemnation in the cartoon; on the contrary, the cat is presented by its creators as a positive character. This is how Matroskin's mother and father of Uncle Fyodor evaluate it - by virtue of their status as parents, they are authoritative persons for the viewer-child.

Mom: "He has a cat, to which you grow and grow. He is behind him, like behind a stone wall."
Dad: "Yes, if I had such a cat, I might never have married" (26:20)

Thus, the creators of the trilogy about Prostokvashino, in the form of a charming petty-bourgeois individualist, managed to legitimize in Soviet culture destructive to Soviet society petty-bourgeois psychology, to impose it on the younger generation as a role model.

Mathematics

Class

Tasks.

1. 10 bushes are planted in a straight line so that the distance between any neighboring bushes is the same. Find this distance if the distance between the extreme bushes is 90 dm.

2. In the entry 1 ☼ 2 ☼ 3 ☼ 4 ☼ 5 = 100, replace "☼" with action signs and arrange the brackets so that you get the correct equality.

3. Boy by even numbers always tells the truth, but always lies on odd numbers. Somehow, for three October days in a row, they asked him: “What is your name?”. On the first day he answered: "Andrey", on the second: "Boris", on the third: "Victor". What is the boy's name? Explain how you reasoned.

4. At 9.00 Yura left the house and walked along a straight road at a speed

6 km/h After a while, he turned around and went home at the same speed. At 12.00 Yura was two kilometers from home. At what distance from the house did he turn around? Explain how the answer was found.

5. Cat Matroskin figured that he could lay out the floor square room square tiles, and he won't need to cut any of them. He first laid the tiles around the edges of the room, and it took him 84 tiles to complete. How many tiles does he need to have to cover the entire floor?

Answers, directions, solutions.

1. Answer . 10 dm.

Decision. Since 10 bushes are planted, there will be 9 gaps between them. Therefore, the distance between adjacent bushes will be 90: 9 = 10dm.

2. Answer . 1 (2 + 3) 4 5 = 100.

3. Answer . Boris.

Decision. Since the boy gave three different answers, he lied twice. Therefore, two days out of three, when the boy was asked questions, fell on odd numbers. Since the even and odd days of the month alternate, these must have been the first and third days. So the second day fell on an even number. On this day, the boy gave his real name.

4. Answer. At a distance of 10 km.

Decision. In 3 hours, from 9.00 to 12.00, Yura walked 18 km. If he will pass two kilometers, then he will get home. That is 18 + 2 = 20 km. - This is the path to the turning point and back. So he turned in the distance

20:2 = 10 km from home.

5. Answer. 484.

Decision. On the border, not counting the corner tiles, there are 84 - 4 = 80 tiles. This means that there are 20 tiles on each side, not counting the corner tiles, and together with the corner tiles there are 22 tiles. So total number tiles is 22 22 = 484.

school stage All-Russian Olympiad schoolchildren

Mathematics

Class

Tasks.

1. The Jumping Dragonfly slept half the time of every day of the red summer, danced a third of the time of every day, and sang a sixth. The rest of the time she decided to devote to preparing for the winter. How many hours a day did the Dragonfly prepare for winter?

2. Aliens told the inhabitants of the Earth that there are three planets A, B, C in their star system. They live on the second planet. Further, the transmission of the message deteriorated due to interference, but two more messages were received, which, as the scientists established, turned out to be both false:

a) A is not the third planet from the star;

b) B is the second planet.

What planets from the star are A, B, C?

3. Mouse, mouse and cheese together weigh 180g. A mouse weighs 100g more than a mouse and cheese combined. Cheese weighs three times less than a mouse. How much does each of them weigh? The answer must be confirmed by calculations.

4. How to cut a square into seven triangles, among which there are six identical ones?

5. There are 24 sticks. The length of the first stick is 1 cm, the second - 2 cm, ..., the twenty-fourth - 24 cm (the length of each next stick is 1 cm longer than the previous one). How, using all these sticks, to make three different squares? You cannot break the sticks, each stick should only fit into one square.

Answers, directions, solutions.

(another solution may be suggested)

1. Answer . 0 hours. There is no time left.

Decision. There are 24 hours in a day, of which the Dragonfly slept 24:2 = 12 hours, danced 24:3 = 8 hours, sang 24:4 = 6 hours. All she spent on these things

12+ 8 + 6 = 24 hours. Therefore, there was no time left to prepare for winter.

2. Answer . B is the first planet, C is the second planet, A is the third planet.

Decision. Since the second and third messages are false, then A is the third planet, and B is not the second, so B is the first planet from the star. Then B will be the second planet inhabited by aliens.

3. Answer. Mouse - 140g, cheese - 10g, mouse - 30g.

Decision. It follows from the condition that the doubled weight of the mouse is 180 + 100 = 280g. Therefore, the weight of the mouse is 140g. Then the mouse and cheese together weigh 180 - 140 \u003d 40g. And the weight of the cheese, according to the condition, equals a quarter this weight.

4. Solution. Two ways to do this are shown in Fig. There are other ways.

Answer.

Decision. Let's divide the sticks into three groups: from 1 to 8, from 9 to 16, from 17 to 24. In each group, we connect the first stick with the last one, the second one with the penultimate one, the third one with the third one from the end, we will also connect the remaining two sticks. We will get four identical sticks in each group, from which we will add a square. Sides of the resulting squares: 9, 25, 41.

Comment. There are other ways to add three squares.

Fifth grade
5.1. At the physical education lesson, the boys lined up in a line. Then between each
a girl stood up as two boys. In total, there were 25 children in the line. How many boys
stood in line?
5.2. Replace the letters A, B, C, D with numbers so that you get the correct equality
AAAA + BBB + CC + D = 2014
5.3. Compose from six rectangles 7x1, 6x1, 5x1, 4x1, 3x1, 2x1 and a 1x1 square
a rectangle with each side greater than 1.
5.4. At 9.00 Yura left the house and walked along a straight road at a speed of 6 km/h. After a while, he turned around and went home at the same speed. At 12.00 Yura had
two kilometers to the house. At what distance from the house did he turn around? Explain how it was
found the answer.
5.5. Cat Matroskin figured that he could lay out the floor of a square room
square tiles, and he won't need to cut any of them. First he put
tiles along the edges of the room, and it took him 84 tiles. How much does he need to have
tiles to cover the entire floor?
Sixth grade
6.1. How to arrange weights weighing 1, 2, ..., 9 g in three boxes so that the first one contains
two weights, in the second - three, in the third - four, and the total weight of the weights in the boxes was
the same?
6.2. The boy on even numbers always tells the truth, and on odd numbers he always lies. How-
then for three November days in a row they asked him: “What is your name?”. On the first day he
answered: "Andrey", on the second: "Boris", on the third: "Victor". What is the boy's name?
Explain how you reasoned.
6.3. Mouse, mouse and cheese together weigh 180g. The mouse weighs 100g more than
mouse and cheese combined. Cheese weighs three times less than a mouse. How much does it weigh
Each of them? The answer must be confirmed by calculations.
6.4. How to cut a square into seven triangles, among which there are six
the same?
6.5. There are 24 sticks. The length of the first stick is 1 cm, the second is 2 cm, ..., twenty
fourth - 24 cm (the length of each next stick is 1 cm longer than the previous one).
How, using all these sticks, to make three different squares? break sticks
it is impossible, each stick should enter only one square.
Seventh grade
7.1. Vasya was visited by his classmates. Vasya's mother asked him how much it came
guests. Vasya answered: “More than six,” and the sister who was standing next to her said: “More than five.”
How many guests were there if it is known that one answer is correct and the other is not?
7.2. There are 25 kg of nails in a box. How to use a pan balance and one weight of 1 kg for two
weighing to measure out 19 kg of nails?
7.3. Petya has four nuts. He is everyone possible ways took three nuts
and weighed them on the scales. It turned out 9 g, 14 g, 16 g and 18 g. How much did each nut weigh?
It is required to find all solutions of the problem and prove that there are no others.
7.4. A square consists of one inner square (black) and four equal white
rectangles (see Fig. 2). The perimeter of each rectangle is 40 cm. Find
the area of ​​the black square.

7.5. Is it possible to line up 30 balls - white, blue and red - so that among any two consecutive balls there is at least one white, among any three
in a row - at least one blue, and among any five going in a row - at least one red?
Explain the answer.
Eighth grade
8.1. Vasya had some money in his wallet. Vasya put another 49 rubles in his wallet,
and the amount of money in the wallet has increased 99 times. How much money did Vasya have in his wallet?
8.2. There are 30 logs with lengths of 3 and 4 m, the total length of which is 100 m.
how many cuts can be made to cut logs into blocks 1 m long? (Exactly one log is sawn with each cut.)
8.3. The number a is such that the lines y = ax + 1, y = x + a and y = 3 are different and intersect at
one point. What can be a?

8.5. At the review of the troops of the Island of Liars and Knights (liars always lie, knights always tell the truth), the leader lined up all the soldiers. Each of the soldiers standing in the line said: "My neighbors in the line are liars." (The warriors standing at the ends of the line said: “My neighbor in the line is a liar.”) What largest number knights could be
in a line, if 2005 soldiers came to the review?
tenth grade

10.1. The gardener-researcher during July and August watched his apple tree. Behind
every month each apple increases the weight by 1.5 times, but at the same time 20% of good apples
become wormy. How and by what percentage did the total weight of good apples change in
the end of August compared to the beginning of July, if at the beginning of July there is not a single wormy apple
did not have?
10.2. At the end of each physical education lesson, the teacher conducts a race and gives the winner
run three sweets, and all the other students - one each. By the end of the quarter, Petya deserved
29 sweets, Kolya - 30, and Vasya - 33 sweets. One of them is known to have missed exactly one
physical education lesson, participating in the Olympiad in mathematics; the rest of the lessons
missed. Which child missed the lesson? Explain your answer.

Eleventh grade

Attached files

Correspondence round of the Olympiad in mathematics.

Those who wish to participate must bring the solution of these tasks on a double piece of paper. 10/14/2014 (Tuesday)

5.1. At the physical education lesson, the boys lined up in a line. Then a girl stood between every two boys. In total, there were 25 children in the line. How many boys were in the line?

5.2. Replace letters A,B,C,D numbers so that the correct equation is AAAA + BBB + CC + D = 2014.

5.3. Make six rectangles 7x1, 6x1, 5x1, 4x1, 3x1, 2x1 and a 1x1 square into a rectangle with each side greater than 1.

5.4. At 9:00, Yura left the house and walked along a straight road at a speed of 6 km/h. After some time, he turned around and went home at the same speed. At 12:00 Yura was 2 kilometers from home. How far from home did he turn around? Explain how the answer was found.

5.5. Cat Matroskin figured that he could lay out the floor of a square room with square tiles, and he would not need to cut any of them. He first laid the tiles around the edges of the room, and it took him 84 tiles to complete. How many tiles does he need to have to cover the entire floor?

Feel free to comment!

5.1. At the physical education lesson, the boys lined up in a line. Then a girl stood between every two boys. In total, there were 25 children in the line. How many boys were in the line?

Answer. 13. Decision. Let's remove the rightmost boy. Then the boys and girls will be equally divided, that is, 12 each. So, there were 12 + 1 = 13 boys in the line.

5.2. Replace the letters A, B, C, D with numbers so that the correct equation is AAAA + BBB + CC + D = 2014.

Answer. 1111 + 888 + 11 + 4 = 2014.

5.3. Make six rectangles 7x1, 6x1, 5x1, 4x1, 3x1, 2x1 and a 1x1 square into a rectangle with each side greater than 1.

Decision. From a 6x1 rectangle and a 1x1 square, we add a 7x1 rectangle. Similarly, we add 7x1 rectangles from pairs of 5x1, 2x1 and 4x1, 3x1 rectangles. The resulting four 7x1 rectangles form a 7x4 rectangle.

5.4. At 9.00 Yura left the house and walked along a straight road at a speed of 6 km/h. After a while, he turned around and went home at the same speed. At 12.00 Yura was two kilometers from home. At what distance from the house did he turn around? Explain how the answer was found.

Answer. At a distance of 10 km. Decision. In 3 hours, from 9.00 to 12.00, Yura walked 18 km. If he walks another two kilometers, he will get home. That is 18 + 2 = 20 km. - This is the path to the turning point and back. So he turned around at a distance of 20:2 = 10 km from home. 5.5. Cat Matroskin figured that he could lay out the floor of a square room with square tiles, and he would not need to cut any of them. He first laid the tiles around the edges of the room, and it took him 84 tiles to complete. How many tiles does he need to have to cover the entire floor? Answer. 484.
Decision. On the border, not counting the corner tiles, there are 84 - 4 = 80 tiles. So, on each
side there are 20 tiles, not counting the corner tiles, and together with the corner tiles - 22 tiles. So
the total number of tiles is 484.

Sixth grade

7.1. Vasya was visited by his classmates. Vasya's mother asked him how many guests had come. Vasya answered: “More than six,” and the sister who was standing next to her said: “More than five.”
How many guests were there if it is known that one answer is correct and the other is not?
Answer. 6.
Decision. Assume that there are indeed more than six guests. Then both Vasya and his sister are right, and this contradicts the condition of the problem. This means that there are no more than six guests and Vasya
not right. But then the sister must be right, otherwise the condition of the problem will be violated again. So there are more than five guests. But if there are more than five and no more than six, then there are exactly six.
7.2. There are 25 kg of nails in a box. How to measure 19 kg of nails using a weighing pan and one weight of 1 kg for two weighings?
Decision. When weighing for the first time, we put a weight on one of the scales and arrange all the nails in the cups so that balance is established. We get 13 and 12 kg of nails.
We set aside the first pile, and divide the rest of the nails in half, weighing without a weight: 12 = 6 + 6. We got the desired number of nails: 19 = 13 + 6
7.3. Petya has four nuts. He took three nuts in every possible way and weighed them on the scales. It turned out 9 g, 14 g, 16 g and 18 g. How much did each nut weigh?
It is required to find all solutions of the problem and prove that there are no others.
Answer. 1, 3, 5, 10.
Decision. In the sum of 9 + 14 + 16 + 18 = 57, the weight of each nut is counted three times, which means that the total weight of all nuts is 19 g. The difference 19 - 9 = 10 is the weight of one of the nuts.
Similarly, we find the weights of the remaining nuts.
7.4. The square consists of one inner square (black) and four equal white rectangles (see Fig. 2). The perimeter of each rectangle is 40 cm. Find
the area of ​​the black square.
Rice. 2
Answer. 400.
Decision. The sum of the lengths of the short and long sides of the rectangle is 20. But this sum is equal to the side of the original square.
7.5. Is it possible to line up 30 balls - white, blue and red - so that among any two balls going in a row there is at least one white, among any three going
in a row - at least one blue, and among any five going in a row - at least one red?
Explain the answer.
Answer. It is forbidden.
First decision. Let's say it's possible. Let's take a red ball that does not lie on the edge (there is at least one of the five balls from the 2nd to the 6th). The balls adjacent to it must
be white, otherwise there will be two neighboring balls, among which there are no white ones. But this means that we have found three consecutive balls, among which there is no blue one.
Second solution. Having divided 30 balls into 15 pairs of adjacent balls, we make sure that among the laid out balls there are at least 15 white ones. Breaking them into 10 triples in a row
balls, we make sure that among the laid out balls there are at least 10 blue ones. Finally, having divided them into 6 fives of consecutive balls, we see that among the laid out balls there are no
less than 6 reds. It turns out that there should be at least 15 + 10 + 6 = 31 balls, and there are only 30 of them.

Eighth grade

_8_klass_2014.doc The decision of the school round of the Olympiad Grade 8
8.1. Vasya had some money in his wallet. Vasya put another 49 rubles in his wallet, and the amount of money in his wallet increased 99 times. How much money did Vasya have in his wallet?
Answer. 49 rubles 50 kopecks.
Decision. Let Vasya have x rubles at the beginning. From the condition of the problem, we obtain that x + 49 = 99x. Solving this equation, we get x = 0.5 rubles = 50 kopecks.
8.2. There are 30 logs with lengths of 3 and 4 m, the total length of which is 100 m. How many cuts can be made to cut the logs into blocks 1 m long? (Each cut
exactly one log is sawn.)
Answer. 70.
First decision. Glue all the logs into one 100-meter log. To divide it into 100 parts, you need to make 99 cuts, of which 29 have already been
made.
Second solution. If there were m three-meter and n four-meter logs, then m + n = 30, 3m + 4n = 100, whence m = 20, n = 10. Therefore, you need to make 202 + 103 = 70
cuts.
8.3. The number a is such that the lines y = ax + 1, y = x + a and y = 3 are different and intersect at one point. What can be a?
Answer. a = 2.
First decision. Note that for x = 1, ax + 1 = x + a = a + 1 is satisfied, so that the point M (1; a + 1) is common for the lines y = ax + 1 and y = x + a. Since straight
different, M is their only common point. Therefore, the line y = 3 must also pass through it, whence a + 1 = 3 and a = 2. It is easy to see that for a = 2 all three lines are really
different.
Second solution. By condition, at the intersection point a x + 1 = x + a  (a - 1)(x - 1) = 0, whence a = 1 or x = 1. But the case a = 1 is impossible, because then the first two lines
would match. Further we argue as in the first solution.